105 - 448找到数组中消失的数字
题目
给定一个范围在 1 ≤ a[i] ≤ n ( n = 数组大小 ) 的 整型数组,数组中的元素一些出现了两次,另一些只出现一次。
找到所有在 [1, n] 范围之间没有出现在数组中的数字。
您能在不使用额外空间且时间复杂度为O(n)的情况下完成这个任务吗? 你可以假定返回的数组不算在额外空间内。
示例:
输入: [4,3,2,7,8,2,3,1]
输出: [5,6]
解答
python里面有一个,判断是否在数组里面的方法。
或者用set先去重,然后排序,然后一个个比对没有的。
加数组长度
作者:haydenmiao 链接:https://leetcode-cn.com/problems/find-all-numbers-disappeared-in-an-array/solution/cyuan-shu-zu-cao-zuo-by-haydenmiao/
因为可能的最大值是数组长度,因此每个值都加一下数组长度,以此来标记,就能区分哪些有哪些没有。
每次加的时候都用%来取消掉加的影响。
func findDisappearedNumbers(nums []int) []int {
if len(nums) == 0 {
return nums
}
for i := 0; i < len(nums); i++ {
index := (nums[i] - 1) % len(nums)
nums[index] += len(nums)
}
res := make([]int, 0, len(nums))
for i := 0; i < len(nums); i++ {
if nums[i] <= len(nums) {
res = append(res, i+1)
}
}
return res
}
Runtime: 384 ms, faster than 57.19% of Go online submissions for Find All Numbers Disappeared in an Array.
Memory Usage: 8.2 MB, less than 75.00% of Go online submissions for Find All Numbers Disappeared in an Array.
/**
* @param {number[]} nums
* @return {number[]}
*/
var findDisappearedNumbers = function (nums) {
if (nums.length === 0) {
return [];
}
for (let i = 0; i < nums.length; i++) {
let index = (nums[i] - 1) % nums.length;
nums[index] += nums.length
}
let res = []
for (let i = 0; i < nums.length; i++) {
if (nums[i] <= nums.length) {
res.push(i + 1)
}
}
return res
};
Runtime: 100 ms, faster than 81.47% of JavaScript online submissions for Find All Numbers Disappeared in an Array.
Memory Usage: 43.7 MB, less than 75.00% of JavaScript online submissions for Find All Numbers Disappeared in an Array.
class Solution:
def findDisappearedNumbers(self, nums: List[int]) -> List[int]:
if len(nums) == 0:
return []
for i in range(len(nums)):
index = (nums[i] - 1) % len(nums)
nums[index] += len(nums)
res = []
for i in range(len(nums)):
if nums[i] <= len(nums):
res.append(i + 1)
return res
Runtime: 460 ms, faster than 14.54% of Python3 online submissions for Find All Numbers Disappeared in an Array.
Memory Usage: 21.6 MB, less than 14.29% of Python3 online submissions for Find All Numbers Disappeared in an Array.
变成负数
作者:gehui1007 链接:https://leetcode-cn.com/problems/find-all-numbers-disappeared-in-an-array/solution/ti-jie-bu-shi-yong-e-wai-kong-jian-by-gehui1007/
class Solution:
def findDisappearedNumbers(self, nums: List[int]) -> List[int]:
for num in nums:
index = abs(num) - 1
nums[index] = -abs(nums[index])
return [i + 1 for i, num in enumerate(nums) if num > 0]
Runtime: 424 ms, faster than 50.58% of Python3 online submissions for Find All Numbers Disappeared in an Array.
Memory Usage: 21.6 MB, less than 14.29% of Python3 online submissions for Find All Numbers Disappeared in an Array.
/**
* @param {number[]} nums
* @return {number[]}
*/
var findDisappearedNumbers = function (nums) {
for (const num of nums) {
let index = Math.abs(num) - 1
nums[index] = -Math.abs(nums[index])
}
let res = []
for (let i = 0; i < nums.length; i++) {
if (nums[i] > 0) {
res.push(i + 1)
}
}
return res
};
Runtime: 96 ms, faster than 88.72% of JavaScript online submissions for Find All Numbers Disappeared in an Array.
Memory Usage: 44 MB, less than 25.00% of JavaScript online submissions for Find All Numbers Disappeared in an Array.
func abs(a int) int {
if a < 0 {
return -a
}
return a
}
func findDisappearedNumbers(nums []int) []int {
for _, value := range nums {
index := abs(value) - 1
nums[index] = -abs(nums[index])
}
res := make([]int, 0, len(nums))
for i := 0; i < len(nums); i++ {
if nums[i] > 0 {
res = append(res, i+1)
}
}
return res
}
Runtime: 376 ms, faster than 81.40% of Go online submissions for Find All Numbers Disappeared in an Array.
Memory Usage: 9 MB, less than 25.00% of Go online submissions for Find All Numbers Disappeared in an Array.
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