189 - 347 前k个高频元素
题目
给定一个非空的整数数组,返回其中出现频率前 k 高的元素。
示例 1:
输入: nums = [1,1,1,2,2,3], k = 2 输出: [1,2]
示例 2:
输入: nums = [1], k = 1 输出: [1]
说明:
你可以假设给定的 k 总是合理的,且 1 ≤ k ≤ 数组中不相同的元素的个数。
你的算法的时间复杂度必须优于 O(n log n) , n 是数组的大小。
解答
第一反应是用map,存一下所有数字出现的频率,然后输出最高的。。
看了题解发现,用hashmap存频率是无法避免的,关键是如何快速有效把高频元素取出来
Runtime: 108 ms, faster than 76.04% of Python3 online submissions for Top K Frequent Elements.
Memory Usage: 17.4 MB, less than 6.25% of Python3 online submissions for Top K Frequent Elements.
python:我有一个方法。。。
Runtime: 104 ms, faster than 88.26% of Python3 online submissions for Top K Frequent Elements.
Memory Usage: 17.2 MB, less than 6.25% of Python3 online submissions for Top K Frequent Elements.
还能更加简洁。。
Runtime: 96 ms, faster than 98.80% of Python3 online submissions for Top K Frequent Elements.
Memory Usage: 17.1 MB, less than 6.25% of Python3 online submissions for Top K Frequent Elements.
Last updated
Was this helpful?