你只能使用标准的栈操作 -- 也就是只有 push to top, peek/pop from top, size, 和 is empty 操作是合法的。
你所使用的语言也许不支持栈。你可以使用 list 或者 deque(双端队列)来模拟一个栈,只要是标准的栈操作即可。
假设所有操作都是有效的 (例如,一个空的队列不会调用 pop 或者 peek 操作)。
解答
/**
* Initialize your data structure here.
*/
var MyQueue = function () {
this.data = []
};
/**
* Push element x to the back of queue.
* @param {number} x
* @return {void}
*/
MyQueue.prototype.push = function (x) {
this.data.push(x)
};
/**
* Removes the element from in front of queue and returns that element.
* @return {number}
*/
MyQueue.prototype.pop = function () {
return this.data.shift()
};
/**
* Get the front element.
* @return {number}
*/
MyQueue.prototype.peek = function () {
return this.data[0]
};
/**
* Returns whether the queue is empty.
* @return {boolean}
*/
MyQueue.prototype.empty = function () {
return this.data.length === 0
};
Runtime: 56 ms, faster than 42.30% of JavaScript online submissions for Implement Queue using Stacks.
Memory Usage: 34 MB, less than 33.33% of JavaScript online submissions for Implement Queue using Stacks.
pop的做法,还可以用shift来完成,本来是写了三行,一下子精简了很多
// 本来的写法
const ans = this.data[0]
this.data = this.data.slice(1)
return ans
go的写法也差不多吧
type MyQueue struct {
data []int
}
/** Initialize your data structure here. */
func Constructor() MyQueue {
return MyQueue{[]int{}}
}
/** Push element x to the back of queue. */
func (this *MyQueue) Push(x int) {
this.data = append(this.data, x)
}
/** Removes the element from in front of queue and returns that element. */
func (this *MyQueue) Pop() int {
result := this.data[0]
this.data = this.data[1:]
return result
}
/** Get the front element. */
func (this *MyQueue) Peek() int {
return this.data[0]
}
/** Returns whether the queue is empty. */
func (this *MyQueue) Empty() bool {
return len(this.data) == 0
}
Runtime: 0 ms, faster than 100.00% of Go online submissions forImplement Queue using Stacks.
Memory Usage: 1.9 MB, less than 75.00% of Go online submissions forImplement Queue using Stacks.