117 - 661 图片平滑器
题目
包含整数的二维矩阵 M 表示一个图片的灰度。你需要设计一个平滑器来让每一个单元的灰度成为平均灰度 (向下舍入) ,平均灰度的计算是周围的8个单元和它本身的值求平均,如果周围的单元格不足八个,则尽可能多的利用它们。
示例 1:
输入: [[1,1,1], [1,0,1], [1,1,1]]
输出: [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
解释: 对于点 (0,0), (0,2), (2,0), (2,2): 平均(3/4) = 平均(0.75) = 0 对于点 (0,1), (1,0), (1,2), (2,1): 平均(5/6) = 平均(0.83333333) = 0 对于点 (1,1): 平均(8/9) = 平均(0.88888889) = 0
注意:
给定矩阵中的整数范围为 [0, 255]。
矩阵的长和宽的范围均为 [1, 150]。
解答
class Solution(object):
def imageSmoother(self, M):
R, C = len(M), len(M[0])
ans = [[0] * C for _ in M]
for r in xrange(R):
for c in xrange(C):
count = 0
for nr in (r-1, r, r+1):
for nc in (c-1, c, c+1):
if 0 <= nr < R and 0 <= nc < C:
ans[r][c] += M[nr][nc]
count += 1
ans[r][c] /= count
return ans
Runtime: 636 ms, faster than 59.90% of Python online submissions for Image Smoother.
Memory Usage: 11.9 MB, less than 100.00% of Python online submissions for Image Smoother.
var imageSmoother = function(M) {
const m = M.length,
n = M[0].length
if (m === 0 || n === 0) {
return [
[]
]
}
const dirs = [
[0, 1],
[0, -1],
[1, 0],
[-1, 0],
[-1, -1],
[1, 1],
[-1, 1],
[1, -1],
]
for (let i = 0; i < m; i++) {
for (let j = 0; j < n; j++) {
let sum = M[i][j],
cnt = 1
for (let k = 0; k < dirs.length; k++) {
let x = i + dirs[k][0],
y = j + dirs[k][1]
if (x < 0 || x > m - 1 || y < 0 || y > n - 1) continue
sum += (M[x][y] & 0xff)
cnt++
}
M[i][j] |= ((sum / cnt) << 8)
}
}
for (let i = 0; i < m; i++) {
for (let j = 0; j < n; j++) {
M[i][j] >>= 8
}
}
return M
};
Runtime: 124 ms, faster than 83.33% of JavaScript online submissions for Image Smoother.
Memory Usage: 42.5 MB, less than 100.00% of JavaScript online submissions for Image Smoother.
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